Triangle Perimeter and Area

Explanation

Triangle perimeter: basic formula and example

The perimeter (*O*) is the sum of all three sides: *O = a + b + c*. Always include units (e.g., cm). Example: a triangle with sides 3 cm, 4 cm, and 5 cm has *O = 3 + 4 + 5 = 12 cm*. If you know only two sides and an angle or a height, you can’t find the perimeter directly—first determine the missing side (with the Law of Cosines or with Pythagoras for a right triangle).

Area: from the basic formula to Heron’s

The basic area formula (*P*) is *P = (a · h_a)/2*, where *h_a* is the height to base *a*. If you know two sides and the included angle *γ*, use *P = (1/2)ab sin γ*. When only the three sides are known, apply Heron’s formula: compute the semiperimeter *s = (a + b + c)/2*, then *P = √(s(s − a)(s − b)(s − c))*. This is especially handy when heights are unknown but side lengths are given.

Special cases: right, isosceles, equilateral

For a right triangle with legs *p* and *q*, *P = (p · q)/2* and *O = p + q + √(p² + q²)*. In an isosceles triangle, you can get the height to the base by halving the base and applying Pythagoras. For an equilateral triangle with side *a*, *O = 3a* and *P = (a²√3)/4*. These “special” forms save time and offer quick plausibility checks.

Common mistakes and quick checks

(1) Check the triangle inequality: for any pair of sides, *a + b > c* (cyclically). (2) Don’t forget units and sensible rounding. (3) With Heron’s formula, the expression under the root must not be negative—if it is, the data are inconsistent. (4) Quick test: for sides 7, 8, and 5, *O = 20 cm*, *s = 10 cm*, and *P = √(10 · 3 · 2 · 5) = √300 ≈ 17.32 cm²*. The result is reasonably smaller than a rough base–height estimate, so it’s plausible. For exams: sketch first, mark the given data, choose the right formula, then compute.

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